What is the limiting reagent between a reaction of HCl(aq) and NaOH(aq)?

FIND A SOLUTION  AT  AmericanWritingHelp.com

GET SOLUTION at academicwritersbay.com
What is the limiting reagent between a reaction of HCl(aq) and NaOH(aq)?

There is no here.
Always start with the balanced chemical equation
##”HCl”_text((aq]) + “NaOH”_text((aq]) -> “NaCl”_text((aq]) + “H”_2″O”_text((l])##
You have a ##1:1## between hydrochloric acid and sodium hydroxide, which means that a complete requires equal number of moles of each reactant.
Now, the number of moles of each reactant can be found by using the and volumes of the two .
##color(blue)(c = n/V implies n = c * V)##
Even without doing any calculations, it should be clear that because you have equal molarities and equal volumes, you will also have equal numbers of moles of hydrochloric acid and sodium hydroxide.
This of course implies that you’re not dealing with a , since you have enough strong base to completely neutralize the strong acid (or vice versa).
So unless the values given to you are incorrect, the answer to this question is that neither the hydrochloric acid, nor the sodium hydroxide acts as a limiting reagent here.
If you want to do some unnecessary math, you can try
##n_(HCl) = “1 mol” color(red)(cancel(color(black)(“dm”^(-3)))) * 50 * 10^(-3)color(red)(cancel(color(black)(“dm”^(3)))) = “0.05 moles HCl”##
What volume of the ##”1-M”## sodium hydroxide solution would contain that many moles of sodium hydroxide?
##c = n/V implies V = n/c##
##V_(NaOH) = (0.050color(red)(cancel(color(black)(“moles”))))/(1color(red)(cancel(color(black)(“mol”)))”dm”^(-3)) = “0.050 dm”^3 = “50 cm”^3##
And there you have it, you have enough moles of strong base to completely neutralize the strong acid.
Assignment status: Solved by our Experts.
Source: © AcademicWritersBay.com

>> 100% ORIGINAL PAPERS FROM AcademicWritersBay.com <<

Assignment status: Already Solved By Our Experts

(USA, AUS, UK & CA  PhD. Writers)

>> CLICK HERE TO ORDER 100% ORIGINAL PAPERS FROM AmericanWritingHelp.com <<

#065

Essay Help Online: Explain how Benedict’s reagent reacts with sugars, including why it does not react with some types of sweeteners.

FIND A SOLUTION  AT  AmericanWritingHelp.com

 Essay Help Online: Explain how Benedict’s reagent reacts with sugars, including why it does not react with some types of sweeteners.
 Why is it important to know sugar content of beverages?  This should include information on health effects of consuming too much sugarDescribe types of sweeteners used in beverages Explain how Benedict’s reagent reacts with sugars, including why it does not react with some types of sweeteners.
Locate 5 different beverages and observed sugar content according to the label.
From what you know about sugar and health, discuss which of these beverages should be limited in consumption
Write an additional paragraph on any interesting information you found in researching sugar content in beverages
Please follow and like us:

Assignment status: Already Solved By Our Experts

(USA, AUS, UK & CA  PhD. Writers)

>> CLICK HERE TO ORDER 100% ORIGINAL PAPERS FROM AmericanWritingHelp.com <<

#075